3x^-3=(7x1/9)

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Solution for 3x^-3=(7x1/9) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x^-3 = (7*x^1)/9 // - (7*x^1)/9

3*x^-3-((7*x^1)/9) = 0

(-7/9)*x+3*x^-3 = 0

3*x^-3-7/9*x = 0

x*(3*x^-4-7/9) = 0

3*x^-4 = 7/9 // : 3

x^-4 = 7/27

-4 < 0

1/(x^4) = 7/27 // * x^4

1 = 7/27*x^4 // : 7/27

27/7 = x^4

x^4 = 27/7 // ^ 1/4

abs(x) = (27/7)^(1/4)

x = (27/7)^(1/4) or x = -(27/7)^(1/4)

x = 0

x = 0

x in { 0} 

x in { (27/7)^(1/4), -(27/7)^(1/4) }

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